In the beginning of class, we went over the questions from the "duck" book on page 585. The answers are below.
82.
a)
q= + 2e-
M = 6.69x10^(-27)kg
V1 Vertical = 0 m/s
V1 Horozontal = 6.0x10^(6)m
v = 500V
a = Fe/m
= qE / m
= qV/mdv
= (2(1.6x10^(-19)c)(500N))/((6.696x10^(.27)kg)(3.0x10^(-2)m))
= 7.97x10^11 m/s ^squared
dV = 0.03m
dH = 0.15m
t = dH/vH
= (0.15m)/(6.0x10^(-8))
= 2.5x10^-8 s
Therefore...............
change in dH = 1/2at^squared
= 1/2(7.97x10^(11)m/s^SQAURED)(2.5x10^(-8) s)^SQUARED
= 2.5x10^-4m or 0.025cm
3.0cm-0.025cm = 2.975cm from negative plate
*NOTE THIS QUESTION WILL NOT BE ON THE TEST*
b)
V2V=V1V+at
= 0 + (7.97x10^(11)m/s^SQUARED))(2.5x10^-8)s)
= 2.0x10^(4)m/s
V =_/(6.00x10^(6)m/s)+(2.0x10^(4)m/s)^SQAURED
= 6.0x10^6 m/s
83)
V = 39(N/C)(m)
D = 0.050m
V = Ed
E = V/d
= 39(N/C)/(0.050m)
= 7.8x10^2 N/C
85)
a)
Fg = Fe
Mg=Eq
mg/q = E
(4)(m)(g)/(2)(q) = E
E = (2(1.67x10^(-27))(9.8m/s^SQAURED))/(1.6x10^(-19)c)
= 2.04x10^-7 N/C
b)
V = (d)(E)
= (.03m)(2.04x10^(-7)N/C)
= 6.12x10^-9 V
86)
E = (v)/(d)
= (90V)/(0.12m)
= 766.67 N/C
87)
d = v/E
= (1200)/(450N/C)
= 0.27m
90)
a)
((m)(q))=((q)(E))
E = (V)/(d)
q = ((2.2x10^(-15)kg)(.0055m))/(280N)
= 4.2x10^-19C
b)
N = c/q
= (4.2x10^(-19))/(1.6x10^(-10))
= 2.6e-
= 3 e-
Today we also got a review for the exams. Questions like 83 and 85 will most likely be on the test this wednesday. STUDY!!
