Showing posts with label Sai. Show all posts
Showing posts with label Sai. Show all posts

Thursday, June 9, 2011

June 9

Answers for circuits booklet

Page 48
1. 3A
2. 6ohms,0.5A
3. 12 ohms
4a. b
4b. a
4c. 4,6
4d. 5
4e. 4,6
4f. b
4g. b

Page 49
1a. 3A
1b. 6A
1c. All 3A EXCEPT for the two bottommost which the answer is 6A
2b. d
3a. 6V
3b. 3A,3A,6A
3b. 12A
3c. 0.5 ohms

Page 50
1.



2.



We also need to answer page 37,38 and 41

Friday, June 3, 2011

Electric Current Booklet!

Answers for pages 44, 45, 46

p. 44

1a. volts
b. voltage
c. current

2a. 1
b. 15
c. 1
d. narrow pipe,thin wire

p. 45

1. 1.5x10^-3 A
2. 4 A
3. 1.2 A
4. 4A
5. 1.5 x 10^-2 A -> 3.0 x 10^-2 A
6. 1000 Ω
7. 10 Ω
8. 100 V
9. Yes the resistance change, case 1: 240 Ω case2: 50 Ω

p. 46

1. R=pL/A, A=pL/R, A= (1.72 x 10^-8 Ω·m )(20 m) / (.10 Ω)
A= 3.44 x 10^-6 m^2

d= sqr(4A/π) d= 2.09 x10^-3 m

2. A= (0.25 x 10^-3 m)(1 x 10^-3m) A=2.5 x 10^-7 m^2

L= RA/p L=(1.5Ω)(2.7 x 10^-7 m^2) / (100 x 10^-8 Ω·m )
L= 0.38m

3. p=RA/L p= (0.04 Ω)(2 x 10^-6 m^2) / 5m
p= 1.6 x 10 ^-8 Ω·m

4. L= RA/p L= (3 Ω)(1.5 x10 ^-6 m^2) / (100 x 10^-8 Ω·m )
L= 4.5m

5. A = pL/R A= ( 55 x 10^-8 Ω·m )(.2m) / .10 Ω
A= 1.1 x 10^-7 m^2

d= sqr(4A/π) d = sqr((4 x 1.1 x 10^-7 m^2) / π)
d= 3.74 x 10 ^-4 m

NOTE:
Nichrome resistivity is 100 x 10^-8 Ω·m
Tungsten resistivity is 55 x 10^-8 Ω·m


We also need to answer the 2 questions on the bottom of page 14 on separate sheet of paper

The next one to scribe is ctc

Tuesday, February 22, 2011

Inclined Plane

Today, four groups answered the questions on page 196, 1 number per group. But only number 3 was solved on the white board. (Second image)
Ms. K also gave an example of a diagram about Forces acting on an inclined plane. (Third image)
We also answered the questions on page 18 of the booklet for Dynamics Unit. The answers are on the back of the booklet.








**We will do Lab experiment about inclined plane tomorrow



The next person to scribe is kun